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Question 1.
40 ml of methane is completely burnt using 80 ml of oxygen at room temperature. The volume of gas left after cooling to room temperature
(a) 40 ml CO2
(b) 40 ml CO2 gas and 80 ml H2o gas
(c) 60 ml CO2 gas and 60 ml H2o gas
(d) 120 ml CO2 gas
Answer:
(a) 40 ml CO2
Solution:
CH4(g) + 2O2 → CO2(g) + 2H2O (1)
Content | CH4 | O2 | CO2 |
Stoichiometric coefficient | 1 | 2 | 1 |
Volume of reactants allowed to react | 40 mL | 80 mL | – |
Volume of reactant reacted and product formed | 40 mL | 80 mL | 40 mL |
Volume of gas after cooling to the room temperature | – | – | – |
Since the product was cooled to room temperature, water exists mostly as liquid. Hence, option (a) is correct.
Question 2.
An element X has the following isotopic composition 200X = 90%, 199X = 8% and 202X = 2%. The weighted average atomic mass of the element X is closest to
(a) 201 u
(b) 202 u
(c) 199 u
(d) 200 u
Answer:
(d) 200 u
Solution:
X = (200×90)+(199×8)+(202×2)100 = 199.96 = 200 u
Question 3.
Assertion:
Two mole of glucose contains 12.044 × 1023 molecules of glucose
Reason:
Total number of entities present in one mole of any substance is equal to 6.02 × 1022
(a) both assertion and reason are true and the reason is the correct explanation of assertion
(b) both assertion and reason are true but reason is not the correct explanation of assertion
(c) assertion is true but reason is false
(d) both assertion and reason are false
Answer:
(c) assertion is true but reason is false
Solution:
Correct reason:
Total number of entities present in one mole of any substance is equal to 6.022 × 1023.
Question 4.
Carbon forms two oxides, namely carbon monoxide and carbon dioxide. The equivalent mass of which element remains constant?
(a) Carbon
(b) Oxygen
(c) both carbon and oxygen
(d) neither carbon nor oxygen
Answer:
(b) Oxygen
Solution:
Reaction 1:
2C + O2 → 2CO
2 × 12g carbon combines with 32g of oxygen. Hence, Equivalent mass of carbon
2×1232 × 8 = 6
Reaction 2:
C + O2 → CO2
12 g carbon combines with 32 g of oxygen. Hence, Equivalent mass of carbon
= 1232 × 8 = 6
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